The displacement of a particle after time t is given by `x = (k // b^(2)) (1 - e^(-bi))`. Where b is a constant. What is the acceleration fo the particle ?

Options

A. `ke^(-bt)`
B. `- ke^(-bt)`
C. `(k)/(b^(2))e^(bt)`
D. `(- k)/(b^(2))e^(-bt)`

Answer

B

Explanation

`v = (dx)/(dt) = (k)/(b^(2)) xx e(-bt) xx b`
`(dv)/(dt) = -ke^(-bt)`