The dot product of 2 vectors is 10 unit and the magnitude of their resultant is 6 units. If we rotate the vectors without changing the magnitude such that they are now perpendicular to each other, what is their new resultant.

Answer

4

Explanation

`vec(a).vec(b) = a b cos theta = 10`
`R^(2) = a^(2) + b^(2) + 2 ab cos theta`
`36 = a^(2) + b^(2) + 2 xx 10`
`a^(2) + b^(2) = 36 - 20 = 16`
`a^(2) + b^(2) = 4^(2)`