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If the position vector of a particle is ...

If the position vector of a particle is given by `vec(r ) = (cos 2t) hat(i) + (sin 2 t) hat(j) + 6 t hat(k) m`. Calculate magnitude of its acceleration (in `m//s^(2)` ) at `t = (pi)/(4)`

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The correct Answer is:
4
`(dvec(r ))/(dt) = -2 sin 2 t hat(i) + 2 cos t hat(j) + 6 hat(k)`
`vec(a) = -4 cos 2 t hat(i) - 4 sin 2 t hat(j)`
`a = 4 m//s^(2)`
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