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A particle moves along the curve y^(2) =...

A particle moves along the curve `y^(2) = 2x` where `x = (t^(2))/(2)` & `y gt 0`. What is the acceleration of the particle at `t = 2s` ?

A

`hat(i)`

B

`hat(j)`

C

`hat(i) - hat(j)`

D

`2 hat(i)`

Text Solution

Verified by Experts

The correct Answer is:
A
`x = (t^(2))/(2)`
`v_(x) = (2t)/(2) rArr a_(x) = hat(i)`
`y^(2) = 2 xx (t^(2))/(2)`
`rArr y = t rArr a_(y) = 0`
`vec(a) = vec(a)_(x) + vec(a)_(y) = hat(i)`
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