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The figure shown below is a system of tw...

The figure shown below is a system of two masses `3 kg` and `6 kg` and massless pulley accelerating upwards with `2 m//s^(2)`. If the value of `T_(2)` is `(288)/(x)N`, then the value of x is

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The correct Answer is:
3
`T_(1) - 30 = 3a_(1)`
`T_(1) - 60 = 6a_(2)`
`a_(1) + a_(2) = 2a_(3) = 2 xx 2`
`a_(1) + a_(2) = 4`
`(T_(1) - 30)/(3) + (T_(1) - 60)/(6) = 4`
`2T_(1) - 60 + T - 60 = 4 xx 6`
`3T_(1) - 120 = 24`
`T_(1) = (144)/(3) N`
`T_(2) = 2T_(1) = (288)/(3) N`
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