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By what acceleration the boy must go up ...

By what acceleration the boy must go up so that `100kg` block remains stationary on the wedge. The wedge is fixed and is smooth `(g =10m//s^(2))`
.

A

`2 ms^(-2)`

B

`4 ms^(-2)`

C

`6 ms^(-2)`

D

`8 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`100 g sin 30^(@) = 800 = T = 50 g + 50a`
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