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Two particles are projected horizontally...

Two particles are projected horizontally with same speed `30 m//s` but in opposite directions from same height at time `t = 0`. Calculate angle between velocity vectors of particles at time `t = 3s`.

A

`0^(@)`

B

`30^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`cos theta = (vec(v)_(1) . vec(v)_(2))/(v_(1) v_(2))`
`= ((30hat(i) - 30 hat(j)))/(30 sqrt2).((-30 hat(i) - 30 hat(j)))/(30 sqrt2) = 0`
`rArr theta = 90^(@)`
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