Find the time when the displacement of the particle becomes zero. Assume velocity and position at `t = 0` to be and `- 10 m` respectively.

Options

A. `1s`
B. `sqrt((5)/(3)) s`
C. `5 s`
D. `2 s`

Answer

C

Explanation

`a = -3t + 5`
`underset(0)overset(v)(int) dv = underset(0)overset(t)(int) (-3t + 5) dt`
`v = (-3 t^(2))/(2) + 5t`
`int dx = underset(0)overset(t)(int) (- (3t^(2))/(2) + 5t) dt`
`Deltax = - (t^(3))/(2) + (5)/(2) t^(2)`
`Deltax = 0`
`rArr (t^(2))/(2) (5 - t) = 0`
`t = 0s " & " t = 5s`