The potential energy of a particle is determined by the expression `U=alpha(x^2+y^2)`, where `alpha` is a positive constant. The particle begins to move from a point with coordinates `(3, 3)`, only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates `(1,1)` is

Options

A. `8 alpha`
B. `24 alpha`
C. `1 b alpha`
D. zero

Answer

C

Explanation

M.E. = U + K = constant
`U_(i) + K_(i) = U_(f) + K_(f)`
`alpha (3^(2) + 3^(2)) + 0 = alpha (1^(2) + 1^(2)) + K_(f)`