A projectile is thrown with a velocity `u_(0)` at an angle `theta` with the horizontal. The ratio of the rate of change of speed w.r.t. time, at highest point to that at the point of projection, is

Options

A. `g sin theta`
B. `- g sin theta`
C. zero
D. g

Answer

C

Explanation

`(dv)/(dt)` (at the top ) = 0
as tangential acceleration at the top = 0
`(dv)/(dt)` (at the starting point) `= g sin theta`
So, required ratio = zero