A particle of mass m is fixed to one end of a light spring of force constant k and unstretched length l. The other end of the spring is fixed on a vertical axis which is rotaing with an angular velocity `omega`. The increase in length of th espring will be

Options

A. `(m omega^(2)l)/(k)`
B. `(m omega^(2) l)/(k - m omega^(2))`
C. `(m omega^(2)l)/(k + m omega^(2))`
D. None of these

Answer

B

Explanation

`kx sin theta = m omega^(2) r = m omega^(2) (l + x) sin theta`