Four particles of masses 1 kg, 2 kg, 3 kg, and 4 kg are situated at the corners of a square and moving at speed `3 ms^(-1), 4 ms^(-1), 1 ms^(-1)` and `2 ms^(-1)` respectively. Each particle maintains a direction towards the particle at the next comer symmetrically. The momentum of the system at this instant is

Options

A. `3 kg ms^(-1)`
B. `5 kg ms^(-1)`
C. `6 kg ms^(-1)`
D. Zero

Answer

D

Explanation

`vec(P)_("system") = m_(1) vec(v)_(1) + m_(2) vec(v)_(2) + m_(3) vec(v)_(3) + m_(4)vec(v)_(4)`
`= 4 (-2 hat(j)) + 3 (-hat(i)) + 4 (+2 hat(j)) + 1 (+3 hat(i)) = 0`