If flat car is given an acceleration `a_(0) = 2 m//s^(2)` staring from rest, computer corresponding tension in the light inextensible string connected to block of mass 50 kg. Neglect mass of pulley and its friction. Coefficient of friction between block and flat car is `mu = 0.30`.

Options

A. `100 N`
B. `250 N`
C. `300 N`
D. `350 N`

Answer

D

Explanation

`L = y + y - x = 2y - x`

Differntiation of above, gives
`2(d^(2)y)/(dt^(2)) - (d^(2)x)/(dt^(2) = 0 " " rArr a_(B) = 2a_(0)`
`T - f = ma_(B)`
`T = mu mg + m xx 2a_(0)`
`= 0.3 xx 50 xx 10 + 50 xx 2 xx 2 = 350 N`