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Consider a quarter circular smooth rod A...

Consider a quarter circular smooth rod AB fixed AB fixed in a vertical plane with centre of the circle at O. A bead of mass m slides without friction with the help of string starting from point A under the action of a constant force `F = 2 gm` as shown in figure.

The velocity of bead when string makes an angle `30^(@)` with the horizontal is nearly :

A

`sqrt(g R (4 sqrt2 - 5))`

B

`2 sqrt(gR)`

C

`sqrt(g R (5 - 2 sqrt3))`

D

`5 sqrt (gR)`

Text Solution

Verified by Experts

The correct Answer is:
A


`theta = 30^(@)`
`Delta POB` becomes an equilateral `Delta`
WET,
`W_(g) + W_(T) + W_(N) = DeltaK`
`- mg R sin theta + (2 mg) [sqrt2 R - R] + 0 = (1)/(2)`
`mv^(2) - 0`
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