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A cat of mass m = 1 kg climbs to a rope ...

A cat of mass m = 1 kg climbs to a rope hung over a leight frictionless pulley. The opposite end of the rope is tied to a weight of mass M = 2m lying on a smooth horizontal plane. What is the tension of the rope where the cat move upwards with in acceleration `a = 2 m//s^(2)` relative to the rope ?

A

2 N

B

12N

C

8N

D

4N

Text Solution

Verified by Experts

The correct Answer is:
4

`vec(a)_("cat") = (2 - a)` upwards `= vec(a)_("cat/Rope") + vec(a)_("rope")`
`T - 1 g = 1 (2 - a)` …(1)
`2T = 2 (a)/(2)` … (2)
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