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10 ml mixture of H(2), CH(4) and CO(2) w...

10 ml mixture of `H_(2), CH_(4)` and `CO_(2)` was exploded with 15 ml of oxygen. After treatment with KOH the vloume reduced by 6 ml and again on treatment with alkaline pyrogallol, the volume further reduced by 3 ml.
Then volume of `H_(2)` in mixture.

A

6 ml

B

1 ml

C

5 ml

D

4 ml

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(H_(2) (g),+,(1)/(2)O_(2) (g),rarr,H_(2)O(l),),(x,,(x)/(2),,,),(-,-,-,,,):}`
`{:(CH_(2) (g),+,2O_(2) (g),rarr,CH_(4) (g),+,2H_(2)O(g),),(y,,2y,,-,,-,),(-,,-,,y,,-,):}`
`CO_(2) (g) + O_(2) (g) rarr x`
`10 - (x + y)`
`V_(CO_(2))` (total) = 6 mL (absorbed by KOH)
`y + 10 - (x - y) = 6`
`10 - x = 6`
`x = 4 mL`
`V_(H_(2)) = 4 mL`
`V_(O_(2)) = 15 - ((x)/(2) + 2y) = 3` (absorbed by alkaline pyrogallol)
`V_(O_(2)) = 12 = (x)/(2) + 2y`
`x + 4y = 24`
`4y = 20`
`y = 5`
`V_(O_(2)) = 5 mL`
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