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A block of mass m kg is placed on a plan...

A block of mass m kg is placed on a plank. The plank is moving with an acceleration `6 hat(i) + 6 hat(j)` (in `m//s^(2)` ). The frictional force acting on the block is `(mu = 0.5, g = 10 m//s^(2))` :

A

6m

B

7m

C

8m

D

`8.5 m`

Text Solution

Verified by Experts

The correct Answer is:
A

`f = ma = 6m`
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