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Mole fraction of x M aqueous urea soluti...

Mole fraction of x M aqueous urea solution is :
[Given : density of solution is `d gm//ml` ]

A

`(18x)/(1000d - 42 x)`

B

`(18 x)/(1000d - 60x)`

C

`(18x)/(1000d - 18x)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
x moles of Urea in 1000 ml of solution
mass of solution = 1000 d gm
mass of solute `60 x gm`
mass of solvent `= (1000d - 60x) gm`
Mole fracction of urea `= (x)/(x + ((1000d - 60x)/(18)))`
`= (18x)/(18x + 1000d - 60x)`
`x_("urea") = (18x)/(1000d - 42x)`
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