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Two sheets of thickness d and 3d and of same area are joined together. Temperature `T_(A), T_(B), T_(C )` shown in the figure are in geometric progression with common ration `r = 3`. Then ratio of thermal conductivity of thinner to thicker sheet is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A

`T_(B) = 3T`
`T_(C ) 3T_(B) = 9T_(A)`
In steady state `P_("in") = P_("out")`
`= K_(2) A_(1) ((T_(B) - T_(C ))/(3d)) = - K_(1) A ((T_(A) - T_(B))/(d))`
`(K_(2))/(3) (-6T_(A)) = K_(1) (-2T_(A))`
`2K_(2) = 2K_(1)`
`(K_(1))/(K_(2)) = (1)/(1)`
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