At temperature T, length of rod is L. If coefficient linear expansion of material of rod is `2 xx 10^(-2)//.^(@)C` then length of rod when temperature of rod increased by `25^(@)C` is

Options

A. `(L)/(2)`
B. L
C. Between L and 2L
D. Greater than 2L

Answer

C

Explanation

`Delta L = L prop Delta T rArr Delta L = L xx 2 xx 10^(-2) xx 25 rArr Delta L = L//2`
`L_(F) = L_(I) + Delta L rArr L_(F) = L + (L)/(2) = (3L)/(2) Ϸ L_(F) = (3L)/(2)`