When x grams of steam at `100^(@)C` is mixed with y grams of ice at `0^(@)C`, we obtain `(x + y)` grams of water at `100^(@)C`. What is the ratio `y//x` ?

Options

A. 1
B. 2
C. 3
D. 4

Answer

C

Explanation

Heat given out when x grams of steam at `100^(@)C` is converted to water at `100^(@)C`
`H_(1) = 540 x` .......(1)
Heat gained by ice at `0^(@)C` to convert to water at `100^(@)C`
`H_(2) = 80y + y xx 1 xx (100 - 0)`
`H_(2) = 180y` ....(2)
According to principle of calorimetry,
`H_(1) = H_(2)`
`540 x = 180 y`
`(y)/(x) = 3`