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What is dimensional formulae of magnetic...

What is dimensional formulae of magnetic field (B) if `F = q v B sin theta`, where F is magnitude of force, q is change, v is speed and B is magnetic field and `theta` is angle between velocity and magnetic field.

A

`[M T^(-2) A^(-1)]`

B

`[M^(-1) T^(2) A]`

C

`[MLT^(-2) A^(-1)]`

D

`[MT^(-3)A^(1)]`

Text Solution

Verified by Experts

The correct Answer is:
A
`F = q VB sin theta`
`[B] = [(F)/(q V sin theta)]`
`= (MLT^(-2))/(ATLT^(-1)) = MT^(-2) A^(-1)`
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Knowledge Check

  • Dimensional formula of magnetic field is :-

    A
    `M^(1)L^(2)T^(-1)A^(-1)`
    B
    `M^(1)L^(0)T^(-2)A^(-1)`
    C
    `M^(1)L^(-2)T^(-1) A^(-1)`
    D
    `M^(1)L^(1)T^(-2)A^(-1) `

  • The dimensional formula for the magnetic field is

    A
    `[MT^(-2)A^(-1)]`
    B
    `[ML^(2)T^(-1)A^(-2)]`
    C
    `[MT^(-2)A^(-2)]`
    D
    `[MT^(-1)A^(-2)]`

  • What is the magnitude and direction of the magnetic field at point B ?

    A
    `3.3xx10^(-5)` T, clockwise
    B
    `6.8xx10^(-5)` T, counterclockwise
    C
    `3.3xx10^(-5)` T, counterclockwise
    D
    `2.7xx10^(-4)` T, clockwise

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