What is dimensional formulae of magnetic field (B) if `F = q v B sin theta`, where F is magnitude of force, q is change, v is speed and B is magnetic field and `theta` is angle between velocity and magnetic field.

Options

A. `[M T^(-2) A^(-1)]`
B. `[M^(-1) T^(2) A]`
C. `[MLT^(-2) A^(-1)]`
D. `[MT^(-3)A^(1)]`

Answer

A

Explanation

`F = q VB sin theta`
`[B] = [(F)/(q V sin theta)]`
`= (MLT^(-2))/(ATLT^(-1)) = MT^(-2) A^(-1)`