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A person can swim in still water with sp...

A person can swim in still water with speed `= 5 km//hr`. He enters a 200m. Wide river at a point A on one of the banks. The river flow velocity is uniform and equal to `6 km//hr`. A point B is located directly across. A, on the other bank. What is the closest possible distance from B where the swimmer can land on the other bank ?

A

`120 m`

B

`40 sqrt(11) m`

C

`30 sqrt(10) m`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

drift min `rArr cos theta = (v_(mr))/(v_(r)) = (-5)/(6)`
drift `= (d)/(v_("mr") sin theta) [v_(r) + v_("mr") cos theta ]`
`= (200)/(5 xx (sqrt11)/(6)) [6 - (25)/(6)] = 40 sqrt11 m`
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