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The moment of inertia of a body about a ...

The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 j`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?

A

`4 sec`

B

`2 sec`

C

`8 sec`

D

`10 sec`

Text Solution

Verified by Experts

The correct Answer is:
B

`(1)/(2) xx 1.2 w^(2) = 1500`
`omega^(2) = (30000)/(1.2)`
`omega = 50`
`omega = "at" rArr t = 2 sec`.
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