Two moles of an ideal gas goes under the process shown in figure. AB and CD are reversible adiabatic process.

The gas under the process is

Options

A. Monoatomic
B. Diatomic
C. Non linear polyatomic
D. Mixture of mononoatmic and non-linear polyatomic

Answer

A

Explanation

`PV^(gamma) =` constant
`P_(0) (2V_(0))^(gamma) = (P)/(32) (16V_(0))^(gamma)`
`P_(0)V_(0)^(gamma) 2^(gamma) = PV_(0)^(gamma) (16^(gamma))/(32)`
`2^(gamma) = (2^(4_(gamma)))/(2^(5))`
`2^(5) = 2^(3_(gamma))`
`5 = 3^(gamma)`
`rho = 5//3` monoatomic gas.