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For an ideal gas :...

For an ideal gas :

A

The change in internal energy in a constant pressure process form temperatures `T_(1)` and `T_(2)` is equal to `nC_(v) (T_(2) - T_(1))` where `C_(v)` is the molar heat capacity at constant volume and n is the number of moles of the gas

B

The change in internal energy and the work done by the gas are equal in magnitude in an adiabatic process

C

The internal energy does not change in isothernal process

D

no heat is added or removed in an adiabatic process

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

(1) `Delta U = nC_(v) (T_(2) - T_(1))` in all processes.
(2) `Delta U = - Delta W`
`|Delta U| = |Delta W|`
( `Delta Q = 0` for adiabatic process)
(3) `Delta U = 0` for isothermal process
(4) `Delta Q = 0` for adiabatic process
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