The position of a particle moving in a string line is given by
`x = 3t^(3) - 18 t^(2) + 36 t`
Here, x is in m and t in second . Then

Options

A. direction of velocity and acceleration both change at `t = 2s`
B. the distance travelled by particle is equal to magnitude of displacement, for `t = 0` to `t = 5s`
C. the speed of particle is decreasing in `t = 0` to `t = 2s` then it is increasing for `t gt 2`
D. the magnitudes of velocity and acceleration are equal at `t = 0`

Answer

B, C, D

Explanation

Displacement is given as
`x = 3t^(3) - 18 t^(2) + 36t`
`rArr v = 3 (t - 2)^(2)`
`a = 18 (t - 2)`