If the reading of spring balance as shown in figure is 2F newton then value of F is (Assume that mass M is in eqyilibrium)

Answer

6

Explanation

`N = mg cos 37^(@)`
`N = 2.5 xx 10 xx (4)/(5)`

Reading of spring balance,
`R = N cos 53^(@)`
`R = 20 xx (3)/(5)`
`R = 12 N`