A force (F) acting on a body is dependent on its desplacement s. as `Fprops^(-1//3)` . Therefore , the power delivered by the force varies with its displacment as

Options

A. `s^(2//3)`
B. `s^(1//2)`
C. `s^(-5//3)`
D. `s^(0)`

Answer

A

Explanation

`F=ks^(-1//3)`
`a=(k)/(m)s^(-1//3)`
`intvdv=(k)/(m)ints^(-1//3)dsrArr(v^(2))/(2)=(k)/(m)[(3s^(2//3))/(2)]`
`vprops^(1//3)`
`P=Fvprops^(-1//3)xxs^(1//3)`
`Pprops^(0)`