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The Th(90)^(232) atom has successive alp...

The `Th_(90)^(232)` atom has successive alpha and beta decays to the end product `Pb_(82)^(208)` . The numbers of alpha and beta. Particles. Emitted in the process respecitvely are-

A

4,6

B

4,4

C

6,2

D

6,4

Text Solution

Verified by Experts

The correct Answer is:
D
Mass number get charge by `rArr4xxn`
because atomic number charge occur only in `alpha`
decay
4n=232-208
4n=24
4n=6
`alpharArr4`
Mass number get charge by `rArr24`
New atomic number `rArr90-6xx2+P`
90-12+P=82
P=94-90=4
`betarArr4`
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