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In Fraumhroffer diffraction pattern due ...

In Fraumhroffer diffraction pattern due to a single slit, the screen is at distance of 100 cm from the slit and slit is illuminated by `lambda=5893Å`. The width of the slit is 0.1 mm. Then separation between central maxima and the first secondary minima

A

`0.5893 cm`

B

`5.893 cm`

C

`0.2946 cm`

D

`2.946 cm `

Text Solution

Verified by Experts

The correct Answer is:
A
`x=(flambda)/(d)=(100xx5893xx10^(-8))/(0.01)`
0.5893 cm
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