A chain consisting of 5 links each of ma...

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically with a constant acceleration of `2.5 m//s^(2)` as shown in the figure. The force of interaction between the top link and the link immediately below it, will be

6.15N

4.92N

3.69N

2046N

Text Solution

Verified by Experts

Let Force between A and B =T
`T=(B+C+D+E)(g+a_(0))`
`T=4m(g+a_(0))`
`=4.(0.1)(12.3)=4.92N`

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