A block of mass M is suspended from a wire of length L, area of cross-section A and Young's modulus Y. The elastic potential energy stored in the wire is

Options

A. `(1)/(2)(M^(2)g^(2)L)/(AY)`
B. `(1)/(2)(Mg)/(ALY)`
C. `(1)/(2)(M^(2)g^(2)A)/(YL)`
D. `(1)/(2)(MgY)/(AL)`

Explanation

`:'kx=mg`
by using `E=(1)/(2)kx^(2)`
we get `U=(1)/(2)(M^(2)g^(2)L)/(AY)`