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Due to a charge inside the cube, the ele...

Due to a charge inside the cube, the electric field is: `E_(x)` = 600x, `E_(y)` = 0, `E_(z)` = 0. The charge inside the cube is nearly -

A

600`mu`C

B

60`mu`C

C

53`mu`C

D

6`mu`C

Text Solution

Verified by Experts

The correct Answer is:
C
`q=varepsilon_(0)(Q_(2)-Q_(1))`
`phi_(2)=E_(2).A`
`phi_(2)=600xx0.2xx0.01=1.2`
`phi_(1)=600xx0.1xx0.01=0.6`
`q=8.85xx10^(-12)xx0.6`
`q=53.10xx10^(-12)`
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