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A, B and C are voltmeters of resistances...

`A, B` and `C` are voltmeters of resistances `R, 1.5R` and `3R` respectively. When some potential difference is applied between `x` and `y` the voltmeter readings are `V_A, V`_B`and `V_C,` then

A

`V_(A)=V_(B)=V_(C)`

B

`V_(A)neV_(B)=V_(C)`

C

`V_(A)=V_(B)neV_(C)`

D

`V_(A)+V_(B)=V_(C)`

Text Solution

Verified by Experts

The correct Answer is:
A


`I_(1)+I_(2)=I " " I_(1)=(2I)/(3)`
`I_(1)xx1.5R=I_(2)xx3RI_(2)=(1)/(3)`
`V_(B)=(21)/(3)xx1.5R=IR`
`V_(C)=(1)/(3)xx3R=IR`
`V_(A)=V_(B)=V_(C)`
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