If mass of `U^(235)=235.12142 a.m.u.`, mass of `U^(236) =236.1205 amu`, and mass of neutron `=1.008665 am u`, then the energy required to remove one neutron from the nucleus of `U^(236)` is nearly about.

Options

A. zero
B. 6.5 MeV
C. 75 MeV
D. 1 cV

Answer

B

Explanation

Given, `m(U^(215))=235.121420`amu
`m(0^(n^(1)))=1.008665`amu
`m(U^(236))=236.123050`amu
Mass defect `triangle m=m(U^(235))+m(0^(n^(1)))-m(U^(236))`
`=235.121420+1.008665-236.123050`
`triangle m=0.007`amu
Energy required to remove one neutron
`=0.007xx931`MeV
`=6.517`MeV`=6.5`MeV