The sides BC;CA and AB of a `Delta ABC`; are produced in order; forming exterior angles `/_ACD;/_BAE and /_CBF`. Show that `/_ACD + /_BAE + /_CBF = 360^@`

The sides BC;Ca and AB of a Delta ABC; are of produced in order; forming exterior angles /_ACD;/_BAE and /_CBF. Show that /_ACD+/_BAE+/_CBF=360

The sides BC,CA and AB of a triangle ABC, are produced in order,forming exterior angles /_ACD,/_BAE and /_CBF. Show that /_ACD+/_BAE+/_CBF=360^(@)

The sides BC,CA and AB of a ABC, are produced in order,forming exterior angles /_ACD,/_BAE and /_CBF .Show that /_ACD+/_BAE+/_CBF=360^(@)

If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is

The sides BC,CA and AB of triangle ABC have been produced to D, E and F respectively as shown in the figure, forming exterior angles angle ACD, angle BAE and angle CBF . Then, angle ACD + angle BAE + angle CBF is equal to

If the sides of a triangle are produced in order, what will be the sum of exterior angles thus formed ?

If the sides of a triangle are produced in order, what will be the sum of exterior angles thus formed ?

If the sides of a triangle are produced in order, what will be the sum of exterior angles thus formed ?

If the sides of a triangle are produced in order, what will be the sum of exterior angles thus formed ?