In an ac circuit `l=100 sin 200 pi t` . The time required for the current to achieve its peak value will be

In an AC circuit I=100sin 200pit . The time required for the current to achieve its peak value of will be

A resistance of 20 ohm is connected to a source of an alternating potential V = 200 cos (100 pi t) . The time taken by the current to change from its peak value to rms value alpha is

The equation of current in an ac circuit is I = 4 sin (100pit + pi//6) ampere. The current at the beginning (t = 0) will be –

In the Ac circuit, the current is expressed as / = 100 sin 200pit. In this circuit the current rises from zero to peak value in time

In the Ac circuit, the current is expressed as / = 100 sin 200pit. In this circuit the current rises from zero to peak value in time

The instantaneous value of current in an ac circuit is I = 2 sin (100pit + pi//3) A . The current at the beginning (t = 0) will be –

An alternating voltage v(t)=220sin100 pi t volt is applied to a purely resistive, load of 50Ω .The time taken for the current to rise from half of the peak value to the peak value is in milliampere.

Equation of an ac is I=10 sin (200pit-pi/15) ampere. Determine the frequency and peak value of the current.