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Consider a square ABCD of side 12 and le...

Consider a square ABCD of side 12 and let M, N be the midpoints of AB, CD respectively. Take a point P on MN and let AP=r, PC=s. Then the area of the triangle whose sides are r, s, 12 is-

A

72

B

36

C

`(rs)/(2)`

D

`(rs)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
B

PA=r, PC = s
So PB = r
Triangle with sides r, s & 12 is `DeltaPCB`

`"area"=(1)/(2)"base"xx"height"=(1)/(2)xx6xx12=36`
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