In Searle's experiment to find young's modulus, the diameter of wire is measured as `D = 0.05 cm` , the length of wire is `L = 125 cm` , and when a weight , `m = 20 kg` is the put , extension in wire was found to be `0.100 cm` . Find the maximum permissible error in Young's modulus (Y).

Explanation

`(mg)/(pid^(2)//4)=Y((x)/(l))rArrY=(mgl)/((pi//4)d^(2)x)`
`((DeltaY)/(Y))_(max)=(Deltam)/(m)+(Deltal)/(l)+2(Deltad)/(d)+(Deltax)/(x)`
here no information of least count is given so maximum permissible error in `l =` place value of last number
`m = 20.0kg rArr Deltam = 0.1 kg` (place value of lat number)
`l = 125cm rArr Deltal = 1cm` (place value of last number )
`d = 0.050 cm rArr Deltad = 0.001 cm` (place value of last number)
`x = 0.100 cm rArr Deltax = 0.001cm` (place value of last number)