To find the value of `g` using simple pendulum. `T=2.00 +-0.01 sec`, `L=1.00+-0.01 m` was measured. Estimate maximum permissible error in `g`. (use `pi^(2)=10`)

To find the value of g using simple pendulum. T=2.00 sec , 1=1.00m was measured. Estimate maximum permissible error in g . (use pi^(2)=10 )

To find the value of g using simple pendulum , T = 2.00 s and l = 1.00 m were measured . Estimate maximum permissible error in g . Also find the value of g .

The error in the measurement of the length of the sample pendulum is 0.2% and the error in time period 4% . The maximum possible error in measurement of (L)/(T^(2)) is

The error in the measurement of length (L) of time simple pendulum is 0.1% and the error in the period (T) is 3%. The maximum possible error in the measurement of (L)/(T^(2)) is

While determining the value of g using simple pendulum, we plot a graph between l and T^(2) which is

In a simple pendulum l=(100.0pm0.5) cm and t=(2.00pm0.01) sec. What is the percentage error in g?

Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .

If L = 2.01 m +- 0.01 m , what is 3L?

In Ohm's law experiment, potential drop across a resistance was measured as v=5.0 volt and current was measured as i=2.00amp . Find the maximum permissible error in resistance.