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In a complete rotation, spindle of a scr...

In a complete rotation, spindle of a screw gauge advances by `(1)/(2)mm`. There are `50` divisions on circular scale. The main scale has `(1)/(2)mm` marks to (is graduated to `(1)/(2)mm`)
If a wire is put between the jaws, `3` main scale divisions are clearly visible, and `20th` division of circular scale coincides with reference line. Find diameter of wire in correct significant figures.

Text Solution

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Diameter of wire `(3 xx (1)/(2)mm) + (20) ((1//2mm)/(50)) = 1.5 + 0.20 = 1.70mm` (The answer should be upto two decimal places because this screwgauges can measure upto 0.01mm accuracy) .
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