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In a certain obervation we got,l = 23.2c...

In a certain obervation we got,`l = 23.2cm,r =1.32cm` and time taken for 10 oscillations was 10.0 s. Find, maximum percentage error in determinaton of 'g'.

Text Solution

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`l = 23.2 rarr Deltal = 0.1 cm`
`l = 23.2 rarr Deltar = 0.01cm`
`t = 10.0 sec rarr Deltat = 0.1 sec`
`((Deltag)/(g))_(max)=((0.1cm+0.1cm)/(23.2cm+1.32cm)+2(0.1sec)/(10.0sec))xx10%=2.44%` .
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