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Time is measured using a stop watch of l...

Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .

Text Solution

Verified by Experts

`T = ("Total time")/("Total oscillation") = (t)/(10)`
`rArr DeltaT = (Deltat)/(10) = (0.1)/(10)`
`DeltaT = 0.01` second .
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