The mass, specific heat capacity and the temperature of a solid are `1000g,(1)/(2) (cal)/g ^(@)C` and `80^(@)C` respectively. The mass of the liquid and the calorimeter are `900g` and `200g`. Initially,both are at room temperature `20^(@)C` Both calorimeter and the solid are made of same material. In the steady state, temperature of mixture is `40^(@)C`, then specific heat capacity of the unknown liquid.

Explanation

`S=((1000)(1//2)(80^(@)-40^(@)))/(900(40^(@)-20^@))-((200)(1//2))/(900)=1cal//gm^(@)C` .