Home
Class 12
PHYSICS
If mass and specific heat capacity of ca...

If mass and specific heat capacity of calormeter is negligible what would be maximum permissible error is `S` Use the data mentioned below `m_(1) rarr 0, S_(c) rarr 0, m_(2) = 1.00kg V = 10.0 V I = 10.0A`
`t = 1.00 xx 10^(2) sec theta_(0) = 15^9@)C` Corrected `theta_(t) = 65^(@)C`
(A) `4%`
(B) `5%` (C) `8%` (D) `12%` .

Text Solution

Verified by Experts

If `m_(1) rarr 0, S_(c) rarr0`
`S_(l) = (Vit)/(m_(2)(theta_(f)-theta_(0))`
`(DeltaS_(l))/(S_(l))=(DeltaV)/(V)+(DeltaI)/(I)+(Deltat)/(t)+(Deltam_(2))/(m_(2))+(Deltatheta_(f)+Deltatheta_(0))/(theta_(f)-theta_(0))=(0.1)/(10.0)+(0.01xx10^(2))/(1.00xx10^(2))+(0.01)/(1.00)+(1+1)/(50)=8%` .
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    RESONANCE|Exercise Exercise|12 Videos

  • EXPERIMENTAL PHYSICS

    RESONANCE|Exercise Exercise -1 PART|1 Videos

  • ELECTROSTATICS

    RESONANCE|Exercise HLP|39 Videos

  • GEOMATRICAL OPTICS

    RESONANCE|Exercise Advance level Problems|35 Videos

Similar Questions

Explore conceptually related problems

To find the value of g using simple pendulum. T=2.00 sec , 1=1.00m was measured. Estimate maximum permissible error in g . (use pi^(2)=10 )

A sphere has mass of (20+-0.4)kg and radius of (10+-0.1) m. Find the maximum percentage error in the measurement of density.

Find the density of ._(6)^(12)C nucleus. Take atomic mass of ._(6)^(12)C as 12.00 am u Take R_(0) =1.2 xx10^(-15) m .

Find the maximum possible percentage error in the measurement of force on an object (of mass m) travelling at velocity v in a circle of radius r, if m= (4.0 pm 0.1)kg, v = (10 pm 0.1) m/s and r=(8.0 pm 0.2)m.

Find the maximum possible percentage error in the measurement of force on an object (of mass m) travelling at velocity v in a circle of radius r if m = (4.0 pm 0.1) kg, v= (10pm0.1) m/s and r= (8.0 pm 0.2) m

Mass and length of a metal cube are 10 kg +- 0.1 kg and 1 m +- 0.02 m . Its density with percentage error is

(lim)_(x rarr0)(1-cos2x)/(x) is a.1b*2c.4d.0

A capillary of internal radius 4 mm , is dipped in water. To how much height, will the water rise in the capillary. ( T_(water) = 70 xx 10^(-3) N//m, g = 10 m//sec^(2), rho_(water) 10^(3) kg//m^(3) , contact angle theta rarr 0 )

Calculate K_(f) for the reaction: M^(3+) + SCN^(Theta) hArr MSCN^(2+) , The [M^(3+)] in the solution is 2.0 xx 10^(-3)M, [SCN^(Theta)] = 1.5 xx 10^(-3)M and Free [SCN^(Theta)] = 1.0 xx 10^(-5)M .