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If emf of battery is 100V, then what was...

If `emf` of battery is `100V`, then what was the resistance of Rheostat adjusted at reading (`i=2A`, `V=20V`)

A

`10Omega`

B

`20Omega`

C

`30Omega`

D

`40Omega`

Text Solution

Verified by Experts

From the curve slope `= (I)/(v) = (1)/(R) = (1)/(10) R = 10Omega`
for second reading `I = (Emf)/(R+R_(rh)) 2 = (100)/(10 + R_(rh)) rArr R_(rh) = 40Omega` .
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