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From some instruments current measured i...

From some instruments current measured is `I=10.0amp`, potential different measured is `V=100.0 V`, length of wire is `31.4 cm`, and diameter of wire is `2.00mm` (all in correct significant figure). The resistivity of wire (in correct significant figures)will be (use `pi=3.14`)

A

`1.00 xx 10^(-4) Omega-m`

B

`1.00 xx 10^(-4) Omega-m`

C

`1.00 xx 10^(-4) Omega-m`

D

`1.00 xx 10^(-4) Omega-m`

Text Solution

Verified by Experts

`rho=(piD^(2))/(4L)=(V)/(L)=((3.14)(2.00xx10^(-3))^(2))/(4(0314))((100.0)/(10.0))`
and answer should be in three `S.F` so `rho = 1.00 xx 10^(-4)Omega -m` .
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