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Two full turns of the circular scale of ...

Two full turns of the circular scale of a screw gauge cover a distance of `1mm` on its main scale. The total number of divisions on the circular scale is `50`. Further, it is found that the screw gauge has a zero error of `- 0.03mm`. While main scale reading of `3mm` and the number of circular scale divisions in line with the main scale as `35`. the dimeter of the wire is

A

`3.32mm`

B

`3.73 mm`

C

`3.67mm`

D

3.38mm`

Text Solution

Verified by Experts

Least count of screw gague
`=(0.5)/(50) mm = 0.01 mm`
`:.` Reading =[Main scale reading + circular scale reading `xx L.C` -(zero error)
`=[3+35 xx 0.01] - (-0.03) = 3.38 MM` .
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Knowledge Check

  • Two full turns of the circular scale of a screw gauge cover a distance of 1 mn on its its main scale . The total number of divisions on the circular scale is 50. Further m it is found that the screw gauge has a zero error of - 0.02 mm . While measuring the diameter of a thin wire , a student notes the main scale reading of 4 mm and the number of circular scale divisions in line with the main scale as 37. The diameter of the wire is

    A
    4.37 mm
    B
    4.39 mm
    C
    4.74 mm
    D
    4.76 mm

  • On six complete rotations, the screw gauge moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is

    A
    0.01 cm
    B
    0.02 mm
    C
    0.001 mm
    D
    0.001 cm

  • Circular scale of a screw gauge moves through 4 divisions of main scale in one rotation. If the number of divisions on the circular scale is 200 and each division of the main scale is 1 mm., the least count of the screw gauge is

    A
    0.01 mm
    B
    0.02 mm
    C
    0.03 mm
    D
    0.04 mm