Home
Class 12
CHEMISTRY
A solution has been prepared by dissolvi...

A solution has been prepared by dissolving 5 g of urea in 95 g of water. What is the mass percent of urea in the solution ?

Text Solution

Verified by Experts

Mass precent `(Mass %) =(Mass of solute)/(Mass os solution)xx100`
M of urea = fg, Mass of water=95g
Mass percent of urea=`((5g))/((5g+95g))xx100=5%`
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution gas been prepared by dissolving 5 g of urea in 95 g of water. What is the mass percent of urea in the solution ?

A solution is prepared by dissolved 2 g of a solute in 36 g of water. Calculate the mass percent of the solute.

A solution is prepared by dissolved 4 g of a solute in 18 g of water. Calculate the mass percent of the solute.

4 g of a solute are dissolved in 36 g of water. What is the mass percent of the solution ?

A solution has been prepared by dissolving 60 g of methyI alcogol in 120 g of water. What are the mole freaction of methyI alcohol and water ?

A solution is prepared by adding 5 g of a substance x to 18 g of water. Calculate the mass percent of the solute.

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea =60 g "mol"^(-1) )

A solution is prepared by dissolving 5.64g of flucose in 60g of water. Calculate the following : (i) mass percent of each of glucose and water (ii) molality of the solution (iii) mole fraction of each of glucose and water.